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Tell students to close their books or devices (or to keep them closed). Reveal one problem at a time. For each problem:
Keep all previous problems and work displayed throughout the talk.
Find the value of each product mentally.
To involve more students in the conversation, consider asking:
Highlight that the product of two fractions can be found by multiplying the numerators and multiplying the denominators.
If students mention "canceling" a numerator and a denominator that share a common factor, demonstrate using the term "dividing" instead. For example, if a student suggests that in the second expression () the 8 in and the 8 in the "cancel out," rephrase the statement by saying that dividing the 8 in the numerator by the 8 in the denominator gives us 1, and multiplying by 1 does not change the other numerator or denominator.
Complete the diagram to show how many s are in 6.
Elena says, “To find , I can take the value of and then either multiply it by or divide it by 2.”
Discuss with your partner why Elena’s method works.
Use the diagram and Elena’s method to find the value of each expression. Think about how to find that value without counting all the pieces in the diagram.
Value of the expression:
Value of the expression:
Value of the expression:
Elena noticed that she always took the same two steps to show division by a fraction on a tape diagram. She said:
“First, I would partition each 1 whole into as many parts as the number in the denominator. For , that number is 4, so the diagram would have 4 times as many parts.
Next, I would put a certain number of those parts into one group. For , I would put 3 of the s into each group and see how many groups there are.”
Which expression represents the result of taking these two steps to find ?
Be prepared to explain your reasoning.