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Select all the expressions that are perfect squares.
\((x+5)(x+5)\)
\((\text- 9 + c)(c-9)\)
\((y-10)(10-y)\)
\((a+3)(3+a)\)
\((2x-1)(2x+1)\)
\((4-3x)(3-4x)\)
\((a+b)(b+a)\)
Each diagram represents the square of an expression or a perfect square.
\((n+7)^2\)
| \(n\) | \(7\) | |
|---|---|---|
| \(n\) | \(n^2\) | \(7n\) |
| \(7\) | \(7n\) | \(7^2\) |
\((5-m)^2\)
| \(5\) | \(\text-m\) | |
|---|---|---|
| \(5\) | \(5^2\) | \(5(\text-m)\) |
| \(\text-m\) | \(5(\text-m)\) | \((\text-m)^2\) |
\((h+\frac13)^2\)
| \(h\) | \(\frac13\) | |
|---|---|---|
| \(h\) | ||
| \(\frac13\) |
| term_1 | term_2 | |
|---|---|---|
| term_1 | cell 1 | cell 2 |
| term_2 | cell 3 | cell 4 |
Solve each equation.
Explain or show why the product of a sum and a difference, such as \((2x+1)(2x-1)\), has no linear term when written in standard form.
To solve the equation \((x+3)^2=4\), Han first expanded the squared expression. Here is his incomplete work:
\(\begin{align}(x+3)^2&=4\\ (x+3)(x+3)&=4\\ x^2+3x+3x+9&=4\\ x^2+6x+9&=4 \end{align}\)
Jada saw the equation \((x+3)^2=4\) and thought, “There are two numbers, 2 and -2, that equal 4 when squared. This means \(x+3\) is either 2 or -2. I can find the values of \(x\) from there.”
Use Jada’s reasoning to solve the equation.
A jar full of marbles is displayed. The following table shows the guesses for 10 people. The actual number of marbles in the jar is 145. Calculate the absolute guessing error for all 10 guesses using \(|\text{guess} - 145|\).
| guess | 190 | 150 | 125 | 133 | 167 | 160 | 148 | 200 | 170 | 115 |
|---|---|---|---|---|---|---|---|---|---|---|
| absolute guessing error |