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The following quadratic expressions all define the same function.
\((x + 5)(x + 3)\)
\(x^2 + 8x +15\)
\((x+4)^2 - 1\)
Select all of the statements that are true about the graph of this function.
The \(y\)-intercept is \((0, \text- 15)\).
The vertex is \((\text- 4, \text- 1)\).
The \(x\)-intercepts are \((\text- 5, 0)\) and \((\text- 3, 0)\).
The \(x\)-intercepts are \((0, 5)\) and \((0, 3)\).
The \(x\)-intercept is \((0, 15)\).
The \(y\)-intercept is \((0, 15)\).
The vertex is \((4, \text- 1)\).
The following expressions all define the same quadratic function.
\((x - 4)(x + 6)\)
\(x^2 + 2x - 24\)
\((x + 1)^2 - 25\)
Here is one way an expression in standard form is rewritten into vertex form.
\(\begin{align}&x^2 - 7x + 6 &\qquad &\text{original expression}\\ &x^2 - 7x + \left(\text-\frac72\right)^2 + 6 -\left(\text- \frac72\right)^2 &\quad&\text{step 1} \\ &\left(x-\frac72\right)^2 + 6-\frac{49}{4} &\quad&\text{step 2}\\ &\left(x-\frac72\right)^2 + \frac{24}{4}-\frac{49}{4} &\quad&\text{step 3}\\ &\left(x-\frac72\right)^2-\frac{25}{4} &\quad&\text{step 4} \end{align}\)
Rewrite each quadratic expression in vertex form.
Select all the equations with irrational solutions.
\(36=x^2\)
\(x^2=\frac14\)
\(x^2=8\)
\(2x^2=8\)
\(x^2=0\)
\(x^2=40\)
\(9=x^2-1\)
Sketch the graph of \(f\).
How is the graph of the equation \(y=(x-1)^2 + 4\) related to the graph of the equation \(y=x^2\)?
The graph of \(y=(x-1)^2 + 4\) is the same as the graph of \(y=x^2\) but is shifted 1 unit to the right and 4 units up.
The graph of \(y=(x-1)^2 + 4\) is the same as the graph of \(y=x^2\) but is shifted 1 unit to the left and 4 units up.
The graph of \(y=(x-1)^2 + 4\) is the same as the graph of \(y=x^2\) but is shifted 1 unit to the right and 4 units down.
The graph of \(y=(x-1)^2 + 4\) is the same as the graph of \(y=x^2\) but is shifted 1 unit to the left and 4 units down.