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The homeowner is worried about the work needed to maintain a grass lawn and flower beds, so she is now looking at some low-maintenance materials.
She is considering artificial turf, which costs \$15 per square foot to install, and gravel, which costs \$3 per square foot. She may use a combination of the two materials in different parts of the yard. Her budget is still \$3,000.
Here is a graph representing some constraints in this situation.
The graph shows a line going through .
The point is located to the right and above the line.
The point is located to the left and below the line.
Select students to share their interpretations of the two points on either side of the line. Make sure that students understand that one point represents a combination of gravel and artificial turf that meets the budget constraint and that the other point does not. The region in which each point belongs can be interpreted in the same way.
Also make sure that students understand why points on the boundary line are included in the solution set of .
To encourage students to evaluate the reasonableness of their solutions in terms of the situation being modeled, discuss questions such as:
A vendor at the Saturday Market makes \$9 profit on each necklace she sells and \$5 profit on each bracelet.
Find a combination of necklaces and bracelets that she could sell in order to make:
Some students may have trouble graphing the line that delineates the solution region from non-solution region because they are used to solving for the variable , but here the variables are and . Ask these students to decide which variable to solve for based on the graph that has been set up. Ask them to notice which quantity is represented by the vertical axis.
If some students plotted discrete points and some shaded the region, choose one of each and display these for all to see. Ask students why each one might be an appropriate representation of the solutions to the inequality.
Highlight that the discrete points represent the situation more accurately, because it is impossible to sell a fraction of a bracelet or 2.75 necklaces. It is, however, tedious to plot a bunch of points to show the solution region. It is much easier to shade the entire region, but with the understanding that, in this situation, only whole-number values make sense as solutions.
A popular band is trying to raise at least \$20,000 for charity by holding multiple concerts at a park. It plans to sell tickets at \$25 each. For each 2-hour concert, the band would need to pay the park \$1,250 in fees for security, cleaning, and traffic services.
The band needs to find the combinations of number of tickets sold, , and number of concerts held, , that would allow it to reach its fundraising goal.
Which combination of tickets and concerts would mean more money for charity:
Some students may find it challenging to graph the boundary line () by identifying the intercepts. The horizontal intercept is fairly easy to find, but the graph intersects the vertical axis at a negative value (and a negative number of concerts does not make sense in this situation). Ask students to find at least one other point (besides the vertical intercept) that is a solution to the equation.
Students who rewrite the equation in slope-intercept form and find the slope to be 0.02 may also find it difficult to interpret. Ask them to try writing the slope as a fraction ().
Invite students to share their inequality and the graph of the solution region.
Focus the discussion on the last two questions—on how students knew which combinations of tickets and concerts would enable the band to meet its goal and would raise more money. Highlight responses that involve testing pairs of values to see if they satisfy the inequality or to make comparisons.
If not mentioned in students' explanations, point out that even though the inequality has a symbol, the solution region is below the boundary line, not above it. Stress the importance of not blindly shading a region based on the symbol in the inequality.