Not all roles available for this page.
Sign in to view assessments and invite other educators
Sign in using your existing Kendall Hunt account. If you don’t have one, create an educator account.
Here is Triangle M.
Han made a copy of Triangle M and composed three different parallelograms using the original M and the copy, as shown here.
For each parallelogram that Han composed, identify a base and a corresponding height, and write the measurements on the drawing.
Find the areas of at least two of these triangles. Show your reasoning.
We can reason about the area of a triangle by using what we know about parallelograms. Here are three general ways to do this:
The area of Parallelogram B is 16 square units because the base is 8 units and the height 2 units. The area of Triangle A is half of that, which is 8 square units.
The area of Parallelogram D is 24 square units because the base is 4 units and the height 6 units. The area of Triangle C is half of that, which is 12 square units.
In the new parallelogram, , , and , so its area is 12 square units. Because the original triangle and the parallelogram are composed of the same parts, the area of the original triangle is also 12 square units.
Draw a rectangle around the triangle. Sometimes the triangle has half of the area of the rectangle.
The large rectangle can be decomposed into smaller rectangles. Each smaller rectangle can be decomposed into two right triangles.
The rectangle on the left has an area of , or 12, square units. Each right triangle inside it is 6 square units in area.
The rectangle on the right has an area of , or 6, square units. Each right triangle inside it is 3 square units in area.
The area of the original triangle is the sum of the areas of a large right triangle and a small right triangle: 9 square units.
Sometimes, the triangle is half of what is left of the rectangle after removing two copies of the smaller right triangles.
The right triangles being removed can be composed into a small rectangle with area square units. What is left is a parallelogram with area , which equals , or 9, square units.
Notice that we can compose the same parallelogram with two copies of the original triangle! The original triangle is half of the parallelogram, so its area is , or 4.5, square units.