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This week, your student will divide whole numbers and decimals. We can think about division as breaking apart a number into equal-size groups.
Let's take \(65 \div 4\) for example. We can imagine that we are sharing 65 dollars equally among 4 people. Here is one way to think about this:
The 65 dollars are divided into 4 equal groups. Everyone gets \(10 + 6 + 0.2 + 0.05\), or 16.25, dollars.
The calculation on the left shows one way to record these steps for dividing.
The calculation on the right shows different intermediate steps, but the quotient is the same. We say that this method of dividing uses partial quotients.
Here is a task to try with your student:
Here is how Jada found \(784 \div 7\) using partial quotients.
Solution
This week, your student will add, subtract, and multiply numbers using what they know about the meaning of the digits.
To add whole numbers and decimal numbers, we can arrange \(0.921 + 4.37\) vertically, aligning the decimal points, and find the sum. This is a convenient way to be sure we are adding digits that correspond to the same units. This also makes it easy to keep track when we compose 10 units into the next higher unit. (Some people call this “carrying.”)
There are a few ways we can multiply two decimals such as \((2.4) \boldcdot (1.3)\). One way is to represent the product as the area of a rectangle. If 2.4 and 1.3 are the side lengths of a rectangle, the product of \((2.4) \boldcdot (1.3)\) is its area.
To find the area, it helps to decompose the rectangle into smaller rectangles by breaking the side lengths apart by place value. In this case, 2.4 can be decomposed into 2 and 0.4, and 1.3 can be decomposed into 1 and 0.3.
Then we can find the area of each smaller rectangle. The sum of the areas of all of the smaller rectangles, 3.12, is the total area.
Here is a task to try with your student:
Find \((2.9) \boldcdot (1.6)\) using an area model and partial products.
Solution: 4.64. The area of the rectangle (or the sum of the partial products) is \(2 + 0.9 + 1.2 + 0.54 = 4.64\)
Earlier, students learned that a division such as \(10 \div 2 = {?}\) can be interpreted as “How many groups of 2 are in 10?” or “How much is in each group if there are 10 in 2 equal-size groups?” They also saw that the relationship between 10, 2, and the unknown number ("?") can also be expressed with multiplication:
\(2 \boldcdot {?}=10\)
\({?} \boldcdot 2=10\)
This week, they use these ideas to divide fractions. For example, \(6 \div 1\frac12 = {?}\) can be thought of as “How many groups of \(1\frac 12\) are in 6?” Expressing the question as a multiplication and drawing a diagram can help us find the answer.
\({?} \boldcdot 1\frac12 = 6\)
From the diagram we can count that there are 4 groups of \(1\frac12\) in 6.
We can also think of \(6 \div 1\frac12 = {?}\) as “How much is in each group if there are \(1\frac12\) equal groups in 6?” A diagram can also be useful here.
From the diagram we can see that there are three \(\frac12\) groups in 6. This means there is 2 in each \(\frac12\) group, or 4 in 1 group.
In both cases, \(6 \div 1\frac12 = 4\), but the 4 can mean different things depending on how the division is interpreted.
Here is a task to try with your student:
Solution:
This week, your student will be thinking about the meaning of division to prepare to learn about division of fractions. Suppose we have 10 liters of water to divide into equal-size groups. We can think of the division \(10 \div 2\) in two ways, or as the answer to two questions:
Here are two diagrams to show the two interpretations of \(10 \div 2\):
In both cases, the answer to the question is 5, but it could mean either “there are 5 bottles with 2 liters in each” or “there are 5 liters in each of the 2 bottles.”
Here is a task to try with your student:
Solution:
Over the next few days, your student will be solving problems that require multiplying and dividing fractions. Some of these problems will be about comparison. For example:
If Priya ran for \(\frac56\) hour and Clare ran for \(\frac32\) hours, what fraction of Clare’s running time was Priya’s running time?
We can draw a diagram and write a multiplication equation to make sense of the situation.
\(\displaystyle \text{(fraction)} \boldcdot \text{(Clare’s time)} = \text {(Priya’s time)}\)
\(\displaystyle {?} \boldcdot \frac32 = \frac56\)
We can find the unknown by dividing. \(\frac56 \div \frac 32 = \frac 56 \boldcdot \frac23\), which equals \(\frac {10}{18}\). So Priya’s running time was \(\frac{10}{18}\), or \(\frac59\), of Clare’s.
Other problems your students will solve are related to geometry—lengths, areas, and volumes. Here are some examples:
We know that the area of a rectangle can be found by multiplying its length and width (\({?} \boldcdot 2\frac12 = 11\frac14\)), so dividing \(11\frac14 \div 2\frac12\) (or \(\frac{45}{4} \div \frac 52\)) will give us the length of the room. \(\frac{45}{4} \div \frac 52 = \frac{45}{4} \boldcdot \frac 25 = \frac92\). The room is \(4\frac12\) meters long.
What is the volume of a box (a rectangular prism) that is \(3\frac12\) feet by 10 feet by \(\frac 14\) foot?
We can find the volume by multiplying the edge lengths. \(3\frac12 \boldcdot 10 \boldcdot \frac14 = \frac72 \boldcdot 10 \boldcdot \frac14\), which equals \(\frac{70}{8}\). So the volume is \(\frac{70}{8}\), or \(8\frac68\), cubic feet.
Here is a task to try with your student:
Solution: