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This activity reminds students of previous work they have done with constant speed situations, using for the relationship between distance, rate, and time. This prepares students for representing movement in opposite directions using signed numbers in following activities.
Students may choose to use strategies such as creating a double number line or table of equivalent ratios to make sense of these problems and come up with a solution. While students are free to use these strategies, ensure that they also understand how to use to represent the relationship between distance traveled, elapsed time, and rate of travel for constant speed situations.
Ask students what they remember about problems involving distance, rate, and time. They might offer that distances traveled and elapsed time create a set of equivalent ratios or that the elapsed time can be multiplied by the speed to give the distance traveled. Give students 1 minute of quiet work time, and follow with a whole-class discussion.
A car is traveling at a constant speed of 60 miles per hour. How far does the car travel in:
The purpose of this discussion is to remind students of how the equation can be used to solve problems involving movement at a constant speed. To find the distance traveled, we can multiply the rate of travel (or speed) by the elapsed time.
Consider drawing a diagram or table to facilitate the discussion of each problem and to remind students of the strategies they used while working with proportional relationships, such as using a scale factor or calculating the constant of proportionality. When relating distance and time in a constant speed situation, the speed is the constant of proportionality.
The purpose of this activity is for students to encounter a concrete situation where multiplying two positive numbers results in a positive number and multiplying a negative and a positive number results in a negative number.
Students use their earlier understanding of a chosen zero point, a location relative to this as a positive or negative quantity, and a description of movement left or right along the number line as negative or positive. They extend their understanding to movement with positive and negative velocities and different times. This situation will produce negative or positive end points depending on whether the velocity is negative or positive. Looking at a number of different examples will help students generalize about the sign of the product of a negative number and a positive number (MP8).
Use Three Reads to support reading comprehension and sense-making about this problem. Display only the problem stem and the diagram, without revealing the questions.
Give students 6–7 minutes of quiet work time, and follow with a whole-class discussion.
A traffic safety engineer was studying traffic patterns. She set up a camera to record the speed and direction of cars and trucks that passed by. She decided to represent positions to the east of the camera with positive numbers and positions to the west of the camera with negative numbers.
A car is traveling east at 12 meters per second. Where will it be 10 seconds after it passes the camera?
A car is traveling west at -14 meters per second. Where will it be 10 seconds after it passes the camera?
| velocity (meters per second) |
time after passing the camera (seconds) |
position (meters) |
equation | |
|---|---|---|---|---|
| car A | +12 | +10 | +120 | |
| car B | -14 | +10 | ||
| car C | +9 | +5 | ||
| car D | -11 | +8 | ||
| car E | -15 | +20 | ||
| car F | +8 | 0 |
Complete the sentences. Be prepared to explain your reasoning.
A positive number times a positive number equals a _______________________.
A negative number times a positive number equals a _______________________.
Encourage students who get stuck to use the provided number line to represent each situation.
The purpose of this discussion is to emphasize that the product of two positive numbers is a positive number and that the product of a positive number and a negative number is a negative number. Begin by displaying the table and the number line from the Task Statement for all to see. Invite students to share their responses and reasoning for each car.
Demonstrate how cars with a positive velocity are moving towards the east and cars with a negative velocity are moving towards the west. Then place a point on the number line to represent each car’s position (except Car E’s position) at the given time. Discuss the following questions:
In this activity, students consider a context of vehicles traveling past a traffic camera at varied constant velocities and in different directions. Students reason about what it means to have a negative time (the vehicle has not yet passed the traffic camera) or a negative velocity (the vehicle is traveling from east to west) in this context. They engage in reasoning abstractly and quantitatively as they represent velocity, distance, and time relationships using an equation, then interpret the results in terms of the situation (MP2).
Students also use repeated reasoning to describe a pattern for identifying the sign of the product of two negative numbers (MP8).
The Launch mentions that this activity is the same context as one in the previous lesson. In this course, the same context of the traffic camera is used in the previous activity of the current lesson.
During the Launch, display this image for all to see:
Ask, “Where was the person 5 seconds after this picture was taken?” (somewhere to the right of the person’s current position) and “Where was the person 5 seconds before this picture was taken?” (somewhere to the left of the person’s current position).
If necessary, point out that if we assume the person is walking at a constant speed, their before and after locations should be equally far from their current position in the image. Ask students how they might represent time in this situation. (5 seconds before the picture was taken could be -5, while 5 seconds after the picture was taken would be +5. The picture was taken when the time was 0.)
Keep students in the same groups. Remind the students of movement east or west as positive or negative velocity.
This activity is the same context as one in the previous lesson, and the questions are related. So students should be able to get to work rather quickly. However, each question requires some careful thought, and one question builds on the other. Consider suggesting that students check in with their partner frequently and explain their thinking. Additionally, you might consider asking students to pause after each question for a quick whole-class discussion before continuing to the next question.
A traffic safety engineer was studying traffic patterns. She set up a camera to record the speed and direction of cars and trucks that passed by. She decided to represent positions to the east of the camera with positive numbers and positions to the west of the camera with negative numbers.
A car was traveling east at 12 meters per second. Where was the car 10 seconds before it passed the camera?
A car was traveling west at -14 meters per second. Where was the car 10 seconds before it passed the camera?
Complete the table to show the position of each vehicle after traveling at a constant velocity for the given amount of time.
| velocity (meters per second) |
time after passing the camera (seconds) |
position (meters) |
equation | |
|---|---|---|---|---|
| car A | +12 | -10 | -120 | |
| car B | -14 | -10 | ||
| car C | +9 | -6 | ||
| car D | -11 | -9 | ||
| car E | -15 | -4 | ||
| car F | +8 | -13 |
Complete the sentences. Be prepared to explain your reasoning.
A positive number times a negative number equals a _______________________.
A negative number times a negative number equals a _______________________.
The key thing for students to understand from this discussion is that a negative number multiplied by another negative number results in a positive number. Begin by displaying the number line and table from the Task Statement for all to see. Invite students to share their responses, and record them in the table.
Then select a car whose equation has a positive and a negative factor, and demonstrate its path on the number line. For example, explain that Car A is traveling from west to east since its velocity is positive. Since its time is represented by a negative number, the car has not yet passed the camera and, therefore, must be located on the left side of the camera, making its position a negative number.
Then select a car whose equation has two negative factors. For example, Car D has a negative velocity, which means that it is traveling from east to west. It also has a negative time, which means it has not yet passed the camera. Car D must be located to the right of the camera, making its position a positive number.
Ask students to complete the sentences in the last problem. Consider posting these in the classroom for all to see for the next few lessons.
To help students consolidate their learning about multiplying signed numbers, consider asking:
We can use signed numbers to represent the position of an object along a line. We pick a point to be the reference point and call it zero. Positions to the right of zero are positive. Positions to the left of zero are negative.
When we combine speed with direction indicated by the sign of the number, it is called velocity. For example, if you are moving 5 meters per second to the right, then your velocity is +5 meters per second. If you are moving 5 meters per second to the left, then your velocity is -5 meters per second.
If you start at zero and move 5 meters per second for 10 seconds, you will be 50 meters to the right of zero. In other words,
If you start at zero and move -5 meters per second for 10 seconds, you will be 50 meters to the left of zero. In other words,
We can also use signed numbers to represent time relative to a chosen point in time. We can think of this as starting a stopwatch. The positive times are after the watch starts, and negative times are times before the watch starts.
If a car is at position 0 and is moving in a positive direction, then for times after that (positive times), it will have a positive position.
For times before that (negative times), it must have had a negative position.
If a car is at position 0 and is moving in a negative direction, then for times after that (positive times), it will have a negative position.
For times before that (negative times), it must have had a positive position.