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The purpose of this Warm-up is to bring up two main methods for figuring out missing numbers in a table that represents a proportional relationship. The two methods students might use for this activity are:
This activity is to get students thinking about the second method as a more efficient method, since it works for every row. This lays the groundwork for solving problems using proportional relationships and for the activities in this lesson.
Introduce the context of this activity by asking students, “When it is hot outside, what do you like to drink to refresh yourself?” Then, explain that people in Mexico make a drink called agua fresca (AH-gwah FREH-skah) by blending fresh fruit with water and ice.
Arrange students in groups of 2. Give 1 minute of quiet work time followed by time to compare their table with a partner. Then hold a whole-class discussion.
A recipe for watermelon agua fresca calls for cup of cubed, seeded watermelon and 1 cup of ice. Complete the table to show how much watermelon and ice to use in different numbers of batches of the recipe.
| watermelon (cups) | ice (cups) |
|---|---|
| 1 | |
| 1 | |
Some students may assume the watermelon column will continue to increase by the same amount if they do not pay close attention to the values in the sugar column. Ask these students what they notice about the values in the sugar column and if it makes sense for the watermelon amount to increase by the same amount each time.
The purpose of this discussion is to contrast two different methods for completing the table: using scale factors between rows and using the constant of proportionality between columns.
Display the table for all to see, and invite students to share their answers and reasoning for each missing entry. Record their ideas directly on the table if possible. Ask students if they agree or disagree with the values in the table.
To help students compare, contrast, and connect the different approaches, consider asking:
If not mentioned by students, highlight that the constant of proportionality is the same for every row in the table, while the scale factor may differ for each pair of rows.
In this activity, students see how an abbreviated table can be used to solve a problem about a proportional relationship. In grade 6, students learned to use a table with 3 rows, where the middle row had a “1” in the left column. Now they learn to use a table with only 2 rows, making use of structure (MP7).
For teachers accustomed to setting up a proportion and cross-multiplying, this approach is structurally very similar. One benefit to using an abbreviated table is that students have the column headings to help make sure they get the numbers in the right places. In addition, students should have a better idea for why they are multiplying and dividing, which is that they are finding and using either a scale factor or the constant of proportionality. In this case, the numbers are selected such that using the constant of proportionality is easier. It is also a natural way to think about calculating the price of any amount of something.
Students should be comfortable with Kiran's method from their work with tables of equivalent ratios in grade 6. However, if needed, show them this even longer solution method first, and let them examine it. Ask why Lin decided to multiply by . Once students are comfortable with the reasoning shown, explain that you will be looking at more efficient ways of solving this problem with a table.
Lin’s method:
Arrange students in groups of 2. Give students 2–3 minutes of quiet work time followed by time for partner discussion. Then hold a whole-class discussion.
Use Collect and Display to create a shared reference that captures students’ developing mathematical language. Collect the language students use to describe how the table can be used to solve the problem. Display words and phrases, such as “row,” “column,” “scale factor,” “constant of proportionality,” “unit price,” and “per.”
Two students are solving the same problem: At a hardware store, they can cut a length of rope off of a big roll so that the customer can buy any length they like. The cost for 6 feet of rope is $7.50. How much would the customer pay for 50 feet of rope at this rate?
Kiran knows he can solve the problem this way.
What would be Kiran's answer?
Kiran wants to know if there is a more efficient way of solving the problem. Priya says she can solve the problem with only 2 rows in the table.
| length of rope (feet) | price of rope (dollars) |
|---|---|
| 6 | 7.50 |
| 50 |
What do you think Priya's method is?
Some students may struggle to progress with Priya's method because the arrows are not drawn in the image and none of the values given are easily divisible. There are many supporting questions that could be asked.
The purpose of this discussion is to highlight how solving this problem can be accomplished in two steps—dividing and multiplying—and to interpret what those two operations represent in terms of the situation.
Direct students’ attention to the reference created using Collect and Display. Ask students to share how the table can be used to solve the problem. Invite students to borrow language from the display as needed. As they respond, update the reference to include additional phrases.
If no students come up with one of these methods, display it for all to see.
Scale factor method:
Constant of proportionality method:
Consider asking:
Although either method will work, there are reasons to prefer using the constant of proportionality to approach problems like these. The constant of proportionality means something important in the situation—it’s the price of 1 foot of rope. Because of that, the 1.25 could be used to easily compute the price of any length of rope. If no students bring it up, point out that the equation could be used to relate any length of rope, , to its price, .
In this activity, students practice using abbreviated tables to solve problems involving proportional relationships. The scaffolding is slowly removed as each problem has less of the table already completed, leaving more of the table for students to fill in.
In this activity, students critique a statement or response that is intentionally unclear, incorrect, or incomplete and improve it by clarifying meaning, correcting errors, and adding details (MP3).
Give students 4–5 minutes of partner work time, and follow with a whole-class discussion.
Tyler swims at a constant speed, 5 meters every 4 seconds. How long does it take him to swim 114 meters?
| distance (meters) | time (seconds) |
|---|---|
| 5 | 4 |
| 114 |
A factory produces 3 bottles of sparkling water for every 8 bottles of plain water. How many bottles of sparkling water does the company produce when it produces 600 bottles of plain water?
| number of bottles of sparkling water |
number of bottles of plain water |
|---|---|
A certain shade of light blue paint is made by mixing quarts of blue paint with 5 quarts of white paint. How much white paint would need to be mixed with 4 quarts of blue paint?
For each of the previous three situations, write an equation to represent the proportional relationship.
Some students may struggle to continue working as the scaffolding is decreased. Consider using these questions to prompt students:
The purpose of this discussion is to highlight how the structure of a table can help identify the calculations that are needed to solve a problem involving a proportional relationship. Invite students to share how they solved the third problem about the paint mixture. Highlight strategies that involved setting up a table.
To get students analyzing the structure of the table, consider asking:
Use Critique, Correct, Clarify to give students an opportunity to improve a sample written response to the question “How much white paint would need to be mixed with 4 quarts of blue paint?” by correcting errors, clarifying meaning, and adding details.
“There are 0.3 quarts of blue paint to white paint, so 1.2 quarts of white paint would be needed.”
Ask, “What parts of this response are unclear, incorrect, or incomplete?”
If time permits, invite students to share the equations they wrote for each proportional relationship. Consider discussing how there are different, equivalent ways to express each relationship and how the equation can be used to help solve the problem.
Optional
In this activity, students solve problems involving proportional relationships and fractions without any tables provided. As students choose to create a table or other representation, they make sense of problems and persevere in solving them (MP1).
Monitor for students who create a table and use the constant of proportionality to find unknown values.
Give students 3–5 minutes of quiet work time, and follow with a whole-class discussion.
If students struggle with getting started, consider asking:
The purpose of this discussion is for students to share how they solved the problems involving proportional relationships with fractions. Invite students to share their method for finding a solution. If time is limited, pick only one of the problems to discuss.
If not mentioned by students, ask students to describe why they chose to calculate the constant of proportionality for this problem and how that helped them with finding the solution.
Share with students, “Today we used tables to solve problems involving proportional relationships with fractions.”
Invite students to share how they use a table with proportional relationships. Here are some questions to elicit student thinking:
If we identify two quantities in a problem and one quantity is proportional to the other, then we can calculate the constant of proportionality and use it to answer other questions about the situation. For example, Andre runs at a constant speed of 5 meters every 2 seconds. How long does it take him to run 91 meters at this rate?
In this problem there are two quantities, time (in seconds) and distance (in meters). Since Andre is running at a constant speed, time is proportional to distance. We can make a table with distance and time as column headers and fill in the given information.
| distance (meters) | time (seconds) |
|---|---|
| 5 | 2 |
| 91 |
To find a value in the right column, we multiply the value in the left column by because . This means that it takes Andre of a second to run 1 meter.
At this rate, it would take Andre , or 36.4, seconds to walk 91 meters. More generally, if is the time it takes to walk meters at that pace, then .