In this activity, students identify expressions that are equivalent to a given expression, which involves applying the distributive property. In order to understand the two ways of solving an equation of the form in upcoming lessons, it is helpful to have some fluency with the distributive property.
Launch
Arrange students in groups of 2. Give 3 minutes of quiet work time and then invite students to share their responses with their partner, followed by a whole-class discussion.
Activity
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Student Task Statement
Select all the expressions equivalent to .
Student Response
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Building on Student Thinking
Activity Synthesis
The purpose of this discussion is to recall that is equivalent to because of the distributive property.
Possible discussion questions:
“What does it mean for expressions to be equivalent?” (They have the same value, no matter what the value of the variable is.)
“Why is equivalent to ?” (because of the distributive property)
“Can you think of another expression that is equivalent to ? (One example is .)
8.2
Activity
15 mins
Either Or
Standards Alignment
Building On
Addressing
7.EE.B.4.a
Solve word problems leading to equations of the form and , where , , and are specific rational numbers. Solve equations of these forms fluently. Compare an algebraic solution to an arithmetic solution, identifying the sequence of the operations used in each approach. For example, the perimeter of a rectangle is cm. Its length is cm. What is its width?
In this activity, students are presented with a balanced hanger diagram and are asked to explain why each of two different equations could represent it. They are then asked to find the unknown weight. Note that no particular solution method is prescribed. Give students a chance to come up with a reasonable approach, and then use the Activity Synthesis to draw connections between the diagram and each of the two equations. Monitor for one student who structures the diagram like , and another like .
When students articulate their reasoning, they have an opportunity to attend to precision in the language they use to describe their thinking (MP6). They might first propose less formal or imprecise language, and after sharing with a partner, revise their explanation to be clearer and stronger.
This activity uses the Stronger and Clearer Each Time math language routine to advance writing, speaking, and listening as students refine mathematical language and ideas.
Launch
Keep students in the same groups. Give 5–10 minutes of quiet work time and time to share their responses with a partner, followed by a whole-class discussion.
Representation: Develop Language and Symbols. Use virtual or concrete manipulatives to connect symbols to concrete objects or values. For example, create a balanced hanger using concrete objects. Be sure to use individual pieces for each part of the diagram. Demonstrate moving pieces off of the hanger to create an equation. Invite students to show different ways to create the same equation. Supports accessibility for: Visual-Spatial Processing, Conceptual Processing
Activity
None
Student Task Statement
Explain why either of these equations could represent this hanger:
or
Find the weight of one circle. Be prepared to explain your reasoning.
Activity Synthesis
The purpose of this discussion is to understand viable alternatives for solving for an unknown weight by reasoning about a hanger diagram. Use Stronger and Clearer Each Time to give students an opportunity to revise and refine their response to why either equation could represent this hanger. In this structured pairing strategy, students bring their first draft response into conversations with 2–3 different partners. They take turns being the speaker and the listener. As the speaker, students share their initial ideas and read their first draft. As the listener, students ask questions and give feedback that will help their partner clarify and strengthen their ideas and writing.
If time allows, display these prompts for feedback:
“The part I understood best was . . . .”
“Can you say more about . . . ?”
“How do you know . . . ? What else do you know is true?”
Close the partner conversations and give students 3–5 minutes to revise their first draft. Encourage students to incorporate any good ideas and words they got from their partners to make their next draft stronger and clearer. If time allows, invite students to compare their first and final drafts. Select 2–3 students to share how their drafts changed and why they made the changes they did.
After Stronger and Clearer Each Time, ask one student to present who divided by 2 first, and another student to present who subtracted 6 first.
If no one mentions one of these approaches, demonstrate it. Show how the hanger supports either approach. The finished work might look like this for the first equation:
For the second equation, rearrange the right side of the hanger, first, so that 2 ’s are on the top and 6 units of weight are on the bottom. Then cross off 6 from each side and divide each side by 2. Show this side by side with “doing the same thing to each side” of the equation.
8.3
Activity
15 mins
Use Hangers to Understand Equation Solving, Again
Standards Alignment
Building On
Addressing
7.EE.B.4.a
Solve word problems leading to equations of the form and , where , , and are specific rational numbers. Solve equations of these forms fluently. Compare an algebraic solution to an arithmetic solution, identifying the sequence of the operations used in each approach. For example, the perimeter of a rectangle is cm. Its length is cm. What is its width?
In this activity, students match hangers to equations, and then solve for an unknown weight first by reasoning about the diagram and then by reasoning about the equation. Monitor for students who:
Rewrite as first.
Divide both sides by first.
This activity uses the Compare and Connect math language routine to advance representing and conversing as students use mathematically precise language in discussion.
Launch
Keep students in the same groups. Give 5–10 minutes of quiet work time and time to share their responses with a partner, followed by a whole-class discussion.
Select work from students with different strategies, such as those described in the Activity Narrative, to share later.
Action and Expression: Internalize Executive Functions. To support development of organizational skills in problem-solving, chunk this task into more manageable parts. For example, show only 2 hangers and 2 equations. If students finish early, assign the remaining hangers and equations. Supports accessibility for: Organization, Attention
Activity
None
Student Task Statement
Here are some balanced hanger diagrams. Each piece is labeled with its weight.
First diagram, left side, two groups, each group has circle x, square 5, right side, rectangle, 16.
Second diagram, left side, two groups, each group has triangle y, square 200, right side, rectangle, 3000.
Third diagram, left side, rectangle 20 point 8, right side 4 groups, each group has pentagon z, square 1 point 1.
Fourth diagram, left side, rectangle, 20 over 3, left side, two groups, each group has crown w and square 2 over 3.
For each diagram:
Explain how to figure out the weight of a piece labeled with a variable by reasoning about the diagram.
Identify which of the following equations matches the diagram. Then explain how to figure out the weight of a piece labeled with a variable by reasoning about the equation.
Activity Synthesis
The purpose of this discussion is to understand different viable methods for solving an equation of the form .
Select one hanger diagram for which one student divided by first and another student distributed first. Display the two solution methods side by side, along with the hanger diagram. Invite students to briefly describe their solution, then use Compare and Connect to help students compare, contrast, and connect the different solutions. Here are some questions for discussion:
“What do the solutions have in common? How are they different?”
“Did anyone solve the problem the same way but would explain it differently?”
“Why do the different approaches lead to the same solutions?”
Lesson Synthesis
Display the equation . Ask one partner to solve by dividing first and the other to solve by distributing first. Then check that both students got the same solution and that it makes the equation true. If students get stuck, encourage them to draw a diagram to represent the equation.
Student Lesson Summary
The balanced hanger diagram shows the amounts on the left equal the amounts on the right. The left side has 3 pieces that each have unknown weight and 3 pieces that each weigh 2 units. So, the left side shows 3 ’s plus 6 units. The right side shows 18 units. We could represent this diagram with an equation and solve the equation the same way we did before.
Since there are 3 groups of on the left, we could represent this hanger with a different equation: .
The two sides of the hanger balance with these weights: 3 groups of on one side, and 18, or 3 groups of 6, on the other side.
Balanced hanger, left side, circle labeled x, square labeled 2, circle labeled x, square labeled 2, circle labeled x, square labeled 2, right side, rectangle not labeled. A dotted line is drawn around three groups, each group contains one circle and one square from the left side and a third of the rectangle on the right side. To the side, an equation says 1/3 * 3 ( x + 2 ) = 1/3 * 18.
The two sides of the hanger will balance with of the weight on each side:
We can remove 2 units of weight from each side, and the hanger will stay balanced. This is the same as subtracting 2 from each side of the equation.
Balanced hanger. Left side, circle labeled x and square labeled 2, the square appears to be loose from the hanger. Right side, rectangle labeled 4 and square labeled 2, the square appears to be loose from the hanger. To the side, an equation says x + 2 - 2= 6 - 2.
An equation for the new balanced hanger is . This gives the solution to the original equation.
Here is a concise way to write the steps above:
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Identify when two expressions are equivalent (i.e., when the two expressions name the same number regardless of which value is substituted into them). For example, the expressions and are equivalent because they name the same number regardless of which number stands for.