Some students may struggle to solve for because of the rational coefficient of in . They may be able to rearrange the equation to but then get stuck at that point. Some strategies for supporting their reasoning:

• Think of simply as a number being multiplied to , so to find , we can divide both sides of the equation by . (Students can still reason this way even if they do not recall or know that dividing by gives the same result as multiplying by . Their resulting equation may look like: .)
• Think of as , and then undo one operation at a time.
• Write as a decimal, 1.8, and divide both sides of the equation by 1.8. (Clarify that, depending on the fraction, rewriting a fraction as a decimal may not always be the most helpful way to go.)

In the course of solving for a variable, students may neglect to apply the distributive property correctly when multiplying a number to an expression. For example, when performing the last step to solve for , they may write , instead of . Remind students that any operation performed on both sides of an equation needs to be applied to all the parts on each side.

Discuss with students:

• "How did you find the inverse of the first function?" (by solving the equation for , or by noting what is done to the temperature in degrees Celsius to get the temperature in degrees Fahrenheit and then reversing the steps.)
• "Suppose we want to find the temperature in degrees Celsius when it is 10 degrees Fahrenheit and when it is 90 degrees Fahrenheit. Which equation would you use? Why?" (the second equation, because it doesn't involve solving an equation, which tends to be quicker)
• "How did you verify that the two equations that relate the temperature in degrees Rankine and the temperature in degrees Celsius are inverse functions?" (by solving the first equation for and seeing if it matches the second equation, or by solving the second equation for and seeing if it matches the first equation)
• "What does each inverse function tell us?" (The first one tells us how to find the temperature in degrees Celsius if we know the temperature in degrees Fahrenheit. The second tells us how to find the temperature in degrees Celsius if we know the temperature in degrees Rankine.)

If time permits, display the graphs of the two functions relating temperature in degrees Celsius and in degrees Fahrenheit. Emphasize how the input and output variables are switched.

The two points on each graph mark the boiling temperature and freezing temperature. In both graphs, the boiling temperature, , is paired with , and the freezing temperature, , is paired with , but the - and -values show up in a different order in the coordinate pairs.)

After students have completed their work, share the correct answers and ask students to discuss the process of solving the problems. Display both equations for all to see, and ask students to compare them. Discuss questions such as:

• "Do both equations define functions? How can we tell?" (Yes. For each price per mug, there is only one possible number of mugs that can be bought. For each number of mugs that the club buys, there is only one possible original price.)
• "In which situation is the first equation more useful?" (when we know the price and want to know how many mugs we can buy)
• "In which situation is the second equation more useful?" (when we know the number of mugs bought and want to know what the original price was)
• "If so, are they inverse functions? How do you know?" (Yes, the two equations “undo” each other. The input of the first function is the output in the second function. The output of the first function becomes the input in the second function.)

Highlight for students how solving the first equation for gives us the second equation and solving the second equation for gives us the first equation.

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Conclude the discussion by inviting 2–3 students to share a norm they identified in action. Provide this sentence frame to help students organize their thoughts in a clear, precise way:

• “I noticed our norm ‘’ in action today, and it really helped me/my group because .”

Invite students to share their response and reasoning. Make sure students see that because the number of seats, , is found by multiplying the number of table, , by 4 and then adding 2, the inverse function can be found by subtracting 2 from and then dividing the result by 4.

Discuss with students:

• "Why are 23 tables needed for 94 guests but 24 tables needed for just 1 more guest?" (Entering 95 for in the equation  gives , but a fractional value of does not make sense in this situation, so one more table is needed, though there will be open seats.)
• "The range of the first function, the set of -values, is numbers that are 2 more than multiples of 4 (6, 10, 14, . . .). In the inverse function, is the domain limited to the same set of -values? Or are numbers like 17 and 85 also possible inputs?"

Highlight that just as solutions to equations need to be interpreted in context, so do the domain and range of a function and its inverse.

• The equation for the first function, , tells us the number of seats at tables, assuming all the tables are filled completely and regardless of whether the seats are occupied by guests. The range values of 6, 10, 14, . . . reflect these assumptions.
• The equation for the inverse function, , gives the number of tables if we know the number of seats, , but we don't assume that the seats completely fill each table. The domain of the inverse function (the set of -values) could include any whole number (not just 6, 10, 14, . . . ). When an input gives a fractional number of table for the output (such as ), we need to interpret it in terms of the situation.