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This week, your student will add and subtract numbers using what they know about the meaning of the digits.
In earlier grades, your student learned that the 2 in 207.5 represents 2 hundreds, the 7 represents 7 ones, and the 5 represents 5 tenths. We add and subtract the digits that correspond to the same units, like hundreds or tenths. For example, to find \(10.5 + 84.3\), we add the tens, the ones, and the tenths separately, so:
\(10+80=90\)
\(0+4=4\)
\(0.5+0.3=0.8\)
Afterward, we combine the tens, ones, and tenths: \(90 + 4 + 0.8 = 94.8\).
Any time we add digits and the sum is greater than 10, we can compose 10 of them into the next higher unit. For example, \(0.9 + 0.3 = 1.2\).
To add whole numbers and decimal numbers, we can arrange \(0.921 + 4.37\) vertically, aligning the decimal points, and find the sum. This is a convenient way to be sure we are adding digits that correspond to the same units. This also makes it easy to keep track when we compose 10 units into the next higher unit. (Some people call this “carrying.”)
Here is a task to try with your student:
Find the value of \(6.54 + 0.768\).
Solution: 7.308. Sample explanation: There are 8 thousandths in 0.768. Next, the 4 hundredths in 6.54 and the 6 hundredths in 0.768 combine make 1 tenth. Together with the 5 tenths in 6.54 and the 7 tenths in 0.768, there are 13 tenths, or 1 one and 3 tenths. In total, there are 7 ones, 3 tenths, no hundredths, and 8 thousandths.
This week, your student will multiply decimals. There are a few ways we can multiply two decimals such as \((2.4) \boldcdot (1.3)\). One way is to represent the product as the area of a rectangle. If 2.4 and 1.3 are the side lengths of a rectangle, the product of \((2.4) \boldcdot (1.3)\) is its area.
To find the area, it helps to decompose the rectangle into smaller rectangles by breaking the side lengths apart by place value. In this case, 2.4 can be decomposed into 2 and 0.4, and 1.3 can be decomposed into 1 and 0.3.
Then, we can find the area of each smaller rectangle. The sum of the areas of all of the smaller rectangles, 3.12, is the total area.
Here is a task to try with your student:
Find \((2.9) \boldcdot (1.6)\) using an area model and partial products.
Solution: 4.64. The area of the rectangle (or the sum of the partial products) is \(2 + 0.9 + 1.2 + 0.54 = 4.64\)
This week, your student will divide whole numbers and decimals. We can think about division as breaking apart a number into equal-size groups.
Let's take \(65 \div 4\) for example. We can imagine that we are sharing 65 dollars equally among 4 people. Here is one way to think about this:
The 65 dollars are divided into 4 equal groups. Everyone gets \(10 + 6 + 0.2 + 0.05\), or 16.25, dollars.
The calculation on the left shows one way to record these steps for dividing.
The calculation on the right shows different intermediate steps, but the quotient is the same. We say that this method of dividing uses partial quotients.
Here is a task to try with your student:
Here is how Jada found \(784 \div 7\) using partial quotients.
Solution