Not all roles available for this page.
Sign in to view assessments and invite other educators
Sign in using your existing Kendall Hunt account. If you don’t have one, create an educator account.
This Warm-up asks students to connect the algebraic representations of systems of equations to the number of solutions. Efficient students will recognize that this can be done without solving the system, but rather by using slope, -intercept, or other methods for recognizing the number of solutions.
Monitor for students who use these methods:
Arrange students in groups of 2. Tell students that each number can be used more than once. Allow students 2 minutes of work time followed by a whole-class discussion.
Select work from students with different strategies, such as those described in the Activity Narrative, to share later.
How many solutions does each system have? Be prepared to share your reasoning.
The goal of this discussion is to compare strategies that students use to find the number of solutions for a system of equations.
Invite a group of students to share their solution and reasoning. Then, ask:
Racing and Play Tickets Cards
In this activity, students apply what they know about systems of linear equations to solve a problem about a real-world situation, but they do not initially have enough information to do so. To bridge the gap, they need to exchange questions and ideas.
The Info Gap structure requires students to make sense of problems by determining what information is necessary, and then to ask for the information that they need to solve the problem. This may take several rounds of discussion if their first requests do not yield the information that they need (MP1). It also allows students to refine the language that they use and to ask increasingly more precise questions until they get the information that they need (MP6).
Tell students that they will solve systems of equations from a situation. Display, for all to see, the Info Gap graphic that illustrates a framework for the routine.
Remind students of the structure of the Info Gap routine, and consider demonstrating the protocol if students are unfamiliar with it.
Arrange students in groups of 2. In each group, give a problem card to one student and a data card to the other student. After reviewing their work on the first problem, give students the cards for a second problem, and instruct them to switch roles.
Your teacher will give you either a problem card, or a data card. Do not show or read your card to your partner.
If your teacher gives you the problem card:
If your teacher gives you the data card:
After students have completed their work, share the correct answers, and ask students to discuss the process of solving the problems. Here are some questions for discussion:
Optional
In this activity, students are presented with a number of scenarios that could be solved using a system of equations. Students are not asked to solve the systems of equations, because the focus at this time is for students to understand how to set up the equations for the system and to understand what the solution represents in context.
Arrange students in groups of 2. Suggest that groups split up the problems so that one person works on the first and third problem while their partner works on the second and fourth. Students may work with their partners to get help when they are stuck, but are encouraged to try to set up the equations on their own first. Partners should discuss their systems and interpretation of the solution after each has had a chance to work on their own.
Allow students 5–7 minutes of partner work time followed by a whole-class discussion.
For each situation:
The focus of the discussion should be on making sense of the context and interpreting the solutions within the context of the problems.
Invite groups to share their systems of equations and interpretation of the solution for each problem. As groups share, record their systems of equations for all to see. When necessary, ask students to explain the meaning of the variables they used. For example, represents the number of minutes the family rides after Lin’s dad starts riding again after taking the picture.
To highlight the connections between the situations and the equations that represent them, ask:
“Would Lin’s dad ever catch up with the family?” (He would not. He started farther back and rides slower than the family. The solution to the system would have a negative value for time, which does not make sense in the context of the problem.)
If students disagree that there is a solution to the modified first problem in which Lin’s dad rides slower than the family, you can display the graph of the modified system and point out the point where the lines intersect. So, although the system has a solution, it is disregarded in this context because it does not make sense.
.Optional
In this activity, students solve a variety of systems of equations, some involving fractions, some involving substitution, and some involving inspection. This gives students a chance to solidify that learning by practicing the methods that they have learned for solving systems of equations.. Some of the systems listed are ones that students could have used in an earlier activity in this lesson, to describe the situations there. In the discussion, students compare the systems here to the ones that they wrote in the earlier activity, and they interpret the answer in context.
Keep students in groups of 2. Allow students 5–7 minutes of partner work time, and follow that with a whole-class discussion.
Here are a lot of systems of equations:
There are two key takeaways from this discussion. The first is to reinforce that for some systems, students can determine—by reasoning—whether it’s possible for a solution to one equation to also be a solution to another equation. The second takeaway is that there are some systems that students will be able to solve only after learning techniques in future grades.
For each problem, ask students to indicate if they identified the system as least or most difficult. Record the responses for all to see.
Bring students' attention to this system:
Ask students what the two equations in the system have in common with each other and to think about whether a solution to the first equation could also be a solution to the second. One can reason that there is no solution because cannot be equal to both 6 and -5.
Ask students to return to the earlier activity and see if they can find any of those systems in these problems. (Lin's family ride is the sixth system. Noah's kayaking trip is the seventh system. Diego's crafting is the eighth system.) After students notice the connection, invite students who chose to solve those systems to interpret the numerical solution of each system in the context of the earlier activity.
Students may be tempted to develop the false impression that all systems where both equations are given as linear combinations can be solved by inspection. Conclude the discussion by displaying this system that students defined in the last activity about birdseed:
Tell students that this system has one solution and they will learn more sophisticated techniques for solving systems of equations like this in future grades.
To wrap up the lessons on solving systems of equations, consider displaying the three systems of equations and asking students how they might begin to solve the systems.
(Both graphing and substitution methods work well)
(Substitution works best)
(Inspection may work best)
If there is time, consider assigning each system to small groups for them to solve and then to share their solutions with the class.
We have learned how to use algebra to solve many kinds of systems of equations that would be difficult to solve by graphing. For example, look at
The first equation says that , so wherever we see , we can substitute the expression instead. So the second equation becomes .
We can solve for :
We know that the -value for the solution is the same for either equation, so we can use either equation to solve for it. Using the first equation, we get:
If we substitute into the other equation, , we get the same value. So the solution to the system is .