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Recall that for any geometric sequence starting at with a common ratio , the sum of the first terms is given by . Find the approximate sum of the first 50 terms of each sequence:
, , , , . . .
, , , , , . . .
In 2010, about 886 thousand homes were sold in the United Kingdom. For the next 3 years, the number of homes sold increased by about 7% annually. Assuming the sales trend continues,
Let’s say you open a savings account with an interest rate of 5% compounded annually (once per year) and that you plan on contributing the same amount to it at the start of every year.
Let’s say you plan to invest \$200 at the start of each year into an account that averages 3% interest compounded annually at the end of the year. How many years until the account has more than \$10,000? \$20,000?
We know that, at the end of year 1, the amount in the account is \$206. At the end of year 2, the amount in the account is \$418.18 since . At the start of year 30, for example, that original \$200 has been compounded a total of 29 times, while the last \$200 deposited has been compounded 0 times. Figuring out how much is in the account 30 years after the first deposit means adding up . We can use the formula for the sum of a geometric sequence, , to find the total amount in the account. The sequence starts at and increases at a rate of each year. After years, the total in the account is . Now we have a simpler expression to evaluate for different -values. It turns out that when , the account has about \$10,301 in it, and when , it has about \$20,682 in it.