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Andre says, “I know that I can find the distance between two points in the plane by drawing in a right triangle and using the Pythagorean Theorem. But I’m not sure how to find the lengths of the legs of the triangle when I can’t just count the squares on the graph.”
Explain to Andre how he can find the lengths of the legs in the triangle in the image. Then, calculate the distance between points and .
The figure shows segment and several points.
| point | point | |
|---|---|---|
| point | ||
| point | ||
| point | ||
| point |
Calculate the slopes of line segments and .
What do you notice about the distances of the points and the slopes of line segments? What does this tell you about the points , , , and ?
Here is a point at and a point .
The diagram shows the point , along with several points that are 5 units away from . For some points, it is easy to see their distance from . For example, we can count or subtract to see that , , and are all 5 units away from .
For other points, we need to calculate the distance. Let's look at the point . To calculate the distance from to , we can let stand for the distance, and set up the Pythagorean Theorem: Evaluate the left-hand side to find that . Now is the positive number that squares to make 25, which means that really is 5 units away from .
The point also looks like it could be 5 units away from . To find its distance from , we can do a similar calculation: . Evaluating the left side, we get . This means that must be a little more than 5. So is not exactly 5 units away from .
To check if any point is 5 units away from the point , we can use the Pythagorean Theorem to see if is equal to 52 or 25.
By the same reasoning, we can check to see if the distance between any points, and , is equal to a distance, , using the equation . When we solve this equation for , we sometimes call this the distance formula: