Sign in to view assessments and invite other educators
Sign in using your existing Kendall Hunt account. If you don’t have one, create an educator account.
Han is looking at the equation \(6x-4+2(5x+2)=16x\).
He says, “I can tell right away there are no solutions, because on the left side, you will have \(6x+10x\) and a bunch of constants, but you have just \(16x\) on the right side.”
Do you agree with Han? Explain your reasoning.