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Give students a brief overview of radioactive dating. Explain that a radioactive element is an element that emits rays or particles of energy when its atoms break down. Some radioactive elements break down at an exponential rate, and their decay rate is measured in terms of half-lives. Carbon-14 is one of those radioactive elements whose decay rate is known: Its half-life is 5,730 years. Because of this, scientists commonly use the amount of carbon-14 in ancient artifacts to estimate their age or date of origin.
Point out that the amount of carbon-14 found in most artifacts is incredibly small. Although carbon is one of the most abundant elements, the most common form of carbon is carbon-12 (which has the same number of protons but a different number of neutrons than carbon-14). For every one part of carbon-14, there are about 1,000,000,000,000 (1 trillion) parts of carbon-12!
Use Three Reads to support reading comprehension and sense-making about this problem. Display only the problem stem and first question, without revealing the table.
Carbon-14 is used to find the age of certain artifacts and fossils. It has a half-life of 5,730 years, so if an object has carbon-14, it loses half of it every 5,730 years.
| number of years after fossil had 3 picograms of carbon-14 |
mass of carbon-14 in picograms |
|---|---|
| 0 | 3 |
| 1,910 | |
| 5,730 | |
| 0.75 |
If students mistake the decay factor after 1,910 years as (or ) because 1,910 is a third of 5,730, and then calculate the amount of carbon-14 left as , or 0.5, picogram, consider asking:
“Can you explain how you found how much carbon-14 remains after 1,910 years.”
“Recall the Warm-up in which we learned that if the four-hour growth factor of an exponential function is, for example, , the hourly growth factor is . How does the four-hour growth factor connect to the hourly growth factor?”
Begin the discussion by inviting students to share how they completed the table, focusing on the second row (1,910 years). Make sure students recall that finding the amount of carbon-14 after 1,910 years means multiplying the original amount (3 picograms) by a factor of , or , because the function at hand is exponential and 1,910 years is of 5,730 years.
Next, select previously identified students to share their strategies for the last question, having as many strategies as possible represented. If no one brings up the fact that the present time is less than four half-lives from 20,000 BCE, which means more than , or , of the carbon-14 remains, point this out. Connect this to the idea of equal factors over equal intervals—the intervals being 5,730 years in this case.
The half-life of carbon-14 is about 5,730 years.
Focus the discussion on the estimates students made and the properties of exponential functions that they used. Here are some questions for discussion:
One thing to note to students is that carbon-14 dating, while improving, is not an exact calculation but rather a good approximation for dating items from long ago. Consider telling students that carbon-14 dating is used only for objects that are less than about 50,000 years old. Ask,