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Consider two equations in a system:
Write a few equations that are equivalent to equation A by multiplying both sides of it by the same number, for example, 2, -5, or . Let’s call the resulting equations A1, A2, and A3. Record your equations here:
Here is a system that you solved earlier, by graphing.
To start solving the system, Elena wrote:
And then she wrote:
Your teacher will give you some slips of paper with systems of equations written on them. Each system represents a step in solving this system:
Arrange the slips in the order that would lead to a solution. Be prepared to:
Here is a system of equations:
To solve this system, Diego wrote these equivalent systems for his first two steps.
Step 1:
Step 2:
Use your equivalent systems to solve the original system. Then, check your solution by substituting the pair of values into the original system.
We now have two algebraic strategies for solving systems of equations: by substitution and by elimination. In some systems, the equations may give us a clue as to which strategy to use. For example:
In this system, is already isolated in one equation. We can solve the system by substituting for in the second equation and finding .
This system is set up nicely for elimination because of the opposite coefficients of the -variable. Adding the two equations eliminates so we can solve for .
In other systems, which strategy to use is less straightforward, either because no variables are isolated, or because no variables have equal or opposite coefficients. For example:
To solve this system by elimination, we first need to rewrite one or both equations so that one variable can be eliminated. To do that, we can multiply both sides of an equation by the same factor. Remember that doing this doesn't change the equality of the two sides of the equation, so the - and -values that make the first equation true also make the new equation true.
There are different ways to eliminate a variable with this approach. For instance, we could:
Multiply Equation B by to get . Subtracting this equation from Equation A eliminates .
Each multiple of an original equation is equivalent to the original equation. So each new pair of equations is equivalent to the original system and has the same solution.
Let’s solve the original system using the first equivalent system we found earlier.
When we solve a system by elimination, we are essentially writing a series of equivalent systems, or systems with the same solution. Each equivalent system gets us closer and closer to the solution of the original system.
Equivalent systems are systems that share the exact same solution set.