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Rewrite each equation so that the expression on one side could be graphed and the \(x\)-intercepts of the graph would show the solutions to the equation.
Here are equations that define quadratic functions \(f, g\), and \(h\). Sketch a graph, by hand or using technology, that represents each equation.
\(f(x)=x^2+4\)
\(g(x) = x(x+3)\)
\(h(x)=(x-1)^2\)
Mai is solving the equation \((x-5)^2=0\). She writes that the solutions are \(x=5\) and \(x=\text- 5\). Han looks at her work and disagrees. He says that only \(x=5\) is a solution. Who do you agree with? Explain your reasoning.
If the equation \((x-4)(x+6)=0\) is true, which is also true according to the zero product property?
Only \(x - 4 = 0\).
Only \(x + 6 = 0\).
\(x - 4 = 0\) or \(x + 6 = 0\).
\(x=\text-4\) or \(x=6\).
To solve the quadratic equation \(3(x-4)^2 = 27\), Andre and Clare wrote the following:
Andre
\(\displaystyle \begin {align} 3(x-4)^2 &= 27 \\ (x-4)^2 &= 9 \\ x^2 - 4^2 &= 9 \\ x^2 - 16 &= 9 \\ x^2 &= 25 \\ x = 5 \quad &\text{ or }\quad x = \text- 5\\ \end {align}\)
Clare
\(\displaystyle \begin{align} 3(x-4)^2 &= 27\\ (x-4)^2 &= 9\\ x-4 &= 3\\ x &= 7\\ \end{align}\)
Decide if each equation has 0, 1, or 2 solutions, and explain how you know.