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Find two numbers that . . .
If you get stuck, try listing all the factors of the first number.
Create a diagram to show that \((x-5)(x+8)\) is equivalent to \(x^2+3x-40\).
Write a \(+\) or a \(-\) sign in each box so the expressions on each side of the equal sign are equivalent.
Match each quadratic expression in standard form with its equivalent expression in factored form.
\(x^2 -2x-35\)
\(x^2 +12x+35\)
\(x^2 +2x-35\)
\(x^2 -12x+35\)
\((x+5)(x+7)\)
\((x-5)(x-7)\)
\((x+5)(x-7)\)
\((x-5)(x+7)\)
Rewrite each expression in factored form. If you get stuck, try drawing a diagram.
Which equation has exactly one solution?
\(x^2=\text-4\)
\((x+5)^2=0\)
\((x+5)(x-5)=0\)
\((x+5)^2=36\)
Elena solves the equation \(x^2=7x\) by dividing both sides by \(x\) to get \(x=7\). She says the solution is 7.
Lin solves the equation \(x^2=7x\) by rewriting the equation to get \(x^2-7x=0\). When she graphs the equation \(y=x^2-7x\), the \(x\)-intercepts are \((0,0)\) and \((7,0)\). She says the solutions are 0 and 7.
Do you agree with either of them? Explain or show how you know.