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Find or estimate the value of each variable mentally.
| 2 | 0.3010 |
| 3 | 0.4771 |
| 4 | 0.6021 |
| 5 | 0.6990 |
| 6 | 0.7782 |
| 7 | 0.8451 |
| 8 | 0.9031 |
| 9 | 0.9542 |
| 10 | 1 |
| 20 | 1.3010 |
| 30 | 1.4771 |
| 40 | 1.6021 |
| 50 | 1.6990 |
| 60 | 1.7782 |
| 70 | 1.8451 |
| 80 | 1.9031 |
| 90 | 1.9542 |
| 100 | 2 |
| 200 | 2.3010 |
| 300 | 2.4771 |
| 400 | 2.6021 |
| 500 | 2.6990 |
| 600 | 2.7782 |
| 700 | 2.8451 |
| 800 | 2.9031 |
| 900 | 2.9542 |
| 1,000 | 3 |
| 2,000 | 3.3010 |
| 3,000 | 3.4771 |
| 4,000 | 3.6021 |
| 5,000 | 3.6990 |
| 6,000 | 3.7782 |
| 7,000 | 3.8451 |
| 8,000 | 3.9031 |
| 9,000 | 3.9542 |
| 10,000 | 4 |
What values could replace the “?” in these equations to make them true?
We know how to solve equations such as
Because
The expression
In the specific case where the base of the logarithm is 10, the “log” can be written without the number 10. For example,
One way to estimate logarithms is with a logarithm table. For example, using this base 10 logarithm table we can see that
| 2 | 0.3010 |
| 3 | 0.4771 |
| 4 | 0.6021 |
| 5 | 0.6990 |
| 6 | 0.7782 |
| 7 | 0.8451 |
| 8 | 0.9031 |
| 9 | 0.9542 |
| 10 | 1 |
| 20 | 1.3010 |
| 30 | 1.4771 |
| 40 | 1.6021 |
| 50 | 1.6990 |
| 60 | 1.7782 |
| 70 | 1.8451 |
| 80 | 1.9031 |
| 90 | 1.9542 |
| 100 | 2 |
| 200 | 2.3010 |
| 300 | 2.4771 |
| 400 | 2.6021 |
| 500 | 2.6990 |
| 600 | 2.7782 |
| 700 | 2.8451 |
| 800 | 2.9031 |
| 900 | 2.9542 |
| 1,000 | 3 |
| 2,000 | 3.3010 |
| 3,000 | 3.4771 |
| 4,000 | 3.6021 |
| 5,000 | 3.6990 |
| 6,000 | 3.7782 |
| 7,000 | 3.8451 |
| 8,000 | 3.9031 |
| 9,000 | 3.9542 |
| 10,000 | 4 |
The logarithm to base 10 of a number